Question

what is the distance covered by a free falling body during the first three seconds of its motion​

Answer 1

Answer:

The first equation shows that, after one second, an object will have fallen a distance of 1/2 × 9.8 × 12 = 4.9 meters.

Explanation:

Answer 2

Answer:

44.1m

Explanation:

s=ut+1/2*gt^2

u=0

t=3s

g=9.8m/s^2

s=0+1/2 *9.8*3^2

s=1/2*9.8*9

s=44.1m

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