Question

What is the distance covered by a freely falling body during the first 3 seconds of its motion. (g=10m/s^2)

Answer 1

Answer:

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Explanation:

GIven : u = 0 m/s ( free falling body)

g (a) = 10 m/s^2

t = 3s

Using equation of motion

s = ut + $\frac{1}{2}$a$t^{2}$

s = 0 + 1/2* (-10) * (3)(3)

s = 1/2 * (-90)

s = -45m

hence the answer is 45 m , do let me know if it is correct.

thanks, have a great day buddy!