Question

What is the distance covered by a freely falling body during the first four seconds of its motion. (g=10m/s2)

Answer 1

Answer:

Hlo Mates

Explanation:

Answer

4.0/5

38

Devanshchaubey

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using 4th eqn. of motion

S(nth)=u+a/2(2n-1)

s is the distance

u is the intial velocity i.e. 0

a =10m/s

n is the no. of seconds

s=0+10/2(2*1-1)

s=10/2(2-1)

s=5*1=5m

the distance covered by the object In a free fall in 1st sec is 5m

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