Physics, asked by mysteriousgirl632, 3 months ago

What is the distance covered by a freely falling body during the first seconds of it's motion ( g = 10 m/s)​

Answers

Answered by khushisaini3054
0

Answer:

Lets line up what we know so far(assuming the body starts from rest):

a = -10

u = 0 (initial velocity)

t = 1

we want to find S (some people use X for distance), so we use the formula S = u*t + 0.5*a*t^2

Therefore S = 0*1 + 0.5*-10*1 = -5

It has moved -5m, in other words, moved downwards five meters.

Answered by vigneshnaik50
0

Answer:

-5 is the answer

Explanation:

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