What is the distance covered by a freely falling body during the first seconds of it's motion ( g = 10 m/s)
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Answer:
Lets line up what we know so far(assuming the body starts from rest):
a = -10
u = 0 (initial velocity)
t = 1
we want to find S (some people use X for distance), so we use the formula S = u*t + 0.5*a*t^2
Therefore S = 0*1 + 0.5*-10*1 = -5
It has moved -5m, in other words, moved downwards five meters.
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Answer:
-5 is the answer
Explanation:
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