Question

What is the distance covered by an object which accelerates from rest with a final velocity of 80 m/s if the time taken is 10 s?

Answer 1

Answer:

hope it will help u

thanku

Answer 2

Answer :-

Distance covered by the object is 400 metres .

Explanation :-

We have :-

→ Initial velocity (u) = 0 m/s

→ Final velocity (v) = 80 m/s

→ Time taken (t) = 10 sec

To find :-

→ Distance covered (s) .

________________________________

Firstly, let's calculate acceleration (a) of the body by using the 1st equation of motion .

v = u + at

⇒ 80 = 0 + a (10)

⇒ 80 = 10a

⇒ a = 80/10

⇒ a = 8 m/s²

Now, we can calculate the distance covered by the object either by using the 2nd or 3rd equation of motion .

v² - u² = 2as

⇒ (80)² - 0 = 2(8)(s)

⇒ 6400 = 16s

⇒ s = 6400/16

⇒ s = 400 m