what is the distance:
during the first two seconds.
between second and tenth seconds.
during the last two seconds
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Answer:
(i) Acceleration during first two seconds =2−04.6−0=2.3m/s2
(ii) Acceleration between second and tenth second is zero, since the velocity is constant during this time.
(iii) Acceleration during last two seconds =12−100−4.6=−2.3m/s2
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