What is the distance from the origin in the plane 2x+3y+6=0
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Step-by-step explanation:
Its normal form is r . (29 2i^−29 3j^+29 4k^)=29 6Hence, the distance of the plane form the origin is 29 6
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Answer:
2x+3x+6=0
2x+3x=0-6
2x+3x=-6
5x=-6
x=-6\5
x=-1.2
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