what is the distance of a needle from a concave mirror of focal length 10cm for which a virtual image of twice its height is formed?
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F = 10cm
height of image = 2 ( height of object )
h1 = 2 × h2 ____________(i)
-v/u = h1 / h2
-v/u = 2 × h2 / h2. ( from (i) )
-v/u = 2
-v = 2u
v = -2u _____________(ii)
1/v - 1/u = 1/f
1/-2u -1/u = 1/ f. ( from (ii) )
-1-2/ u = 1/f
-3/ u = 1/ 10
-3 × 10 = u
u = -30 cm
The distance of a needle from a concave mirror is -30 cm
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