Math, asked by sanyaaingh, 5 months ago

what is the distance of a point P(-5,6) from origin​

Answers

Answered by Anonymous
10

Step-by-step explanation:

distance

√(0+5)^2+(0-6)^2

√25+36

√61

Mark as brilliant and take thanks for all question

Answered by pulakmath007
0

SOLUTION

TO DETERMINE

The distance of a point P(-5,6) from origin

CONCEPT TO BE IMPLEMENTED

For the given two points  \sf{A( x_1 , y_1) \:  \: and \:  \: B( x_2 , y_2)} the distance between the points

 =  \sf{ \sqrt{ {(x_2 -x_1 )}^{2}  + {(y_2 -y_1 )}^{2} } }

EVALUATION

Here the given point is P( - 5, 6)

The origin is (0,0)

Hence the required distance of the point P(-5,6) from origin

 \sf =  \sqrt{ {( - 5 - 0)}^{2} +  {(6 - 0)}^{2}  }  \:  \: unit

 \sf =  \sqrt{ {( - 5 )}^{2} +  {(6 )}^{2}  }  \:  \: unit

 \sf =  \sqrt{25 + 36 }  \:  \: unit

 \sf =  \sqrt{61 }  \:  \: unit

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

1. locate the following points on the cartesian plane(aEr) (0,a),(a,0),(-a, 0),(0,-a)...

https://brainly.in/question/26822338

2. Distance of a point A(-2,0) from x-axis is _______ units.

https://brainly.in/question/28760447

Similar questions