Question

what is the distance of point 234 to the xy plane​

Answer 1

Answer:

Given the point is (2,3,5).

If we draw a perpendicular from the point (2,3,5) on xy− plane then the foot of the perpendicular is (2,3,0).

Now the distance of the point (2,3,5) from the xy− plane is the distance between the ponts (2,3,5) and (2,3,0) and that is

(2−2)

2

+(3−3)

2

+(5−0)

2

=

5

2

=5 units.

So the required distance is 5 units.