what is the distance of the line 4x + 7y + 5 = 0 from the point (1,2)along the line
2x -y = 0?
this question is related to straight lines chapter
Answers
Answered by
1
the given point is (1,2) which is on the line 2x-y=0
the distance frm the given point (1,2) to the line 4x+7y+5=0 is
=4(1)+7(2)+5/√(4²+7²)
=4+14+5/√(16+49)
=23/√65
the distance frm the given point (1,2) to the line 4x+7y+5=0 is
=4(1)+7(2)+5/√(4²+7²)
=4+14+5/√(16+49)
=23/√65
Answered by
0
the answer is 2x + 7y + 5
Similar questions