Question

what is the distance of the point (1, -2, 3) from z axis​. With full solution​

Answer 1

Answer: sqrt (x^2 + y^2+ 4y -2x+14) units

Step-by-step explanation:

any point at z axis = ( x,y,0)

the given point is = (1,-2,3)

we have distance formula r = sqrt((x2-x1)^2+(y2-y1)^2+(z2-z1)^2)

thus substituting we get sqrt((x-1)^2+(y+2)^2+(0-3)^2)

on solving the above equation we get R= x^2+y^2+4y-2x+14