Question

what is the distance travelled by a particle in 4sec if it is projected upward with 30m/s​

Answer 1

Answer:

initial velocity, u = 30 m/s

as the body is projected vertically upwards, a=-g=9.8\ m/s^2

At t = 4 s

s=30\ m/s\times 4\ s-\dfrac{1}{2}\times 9.8\ m/s^2\times (4\ s)^2

s = 41.6 m

Explanation:

Answer 2

Answer:

$s = ut + \frac{1}{2} g {t}^{2}$

Explanation:

$30 \times 4 - \frac{1}{2} 10 \times {4 }^{2} \\ \\ = 120 - 80 \: \: = 40$