what is the distance travelled by an object from time 5 sec to 14 sec if velocity is 30 m/s
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1
Answer:
1124 I think it is a answer
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0
Answer:
202.5
Explanation:
the distance= the area covered under the graph(in velocity time graph)
area=9×15(area of rectangle)+9×15/2(area of upper triangle)
=9×15(1+1/2)
=135(3/2)
=202.5
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