Question

What is the distance travelled during retarded motion? (a) 30 m (b) 40 m (c) 50 m (d) 60 m​

Answer 1

Answer:

Explanation:

(c) 50 m

Answer 2

Answer:

The distance traveled during retarded motion is 50 m.

Explanation:

Let's consider the motion from D to E only. D is the initial point and E is the final point.

Initial velocity, u = 25 m/s

Final velocity, v = 0 m/s

Time taken, t = 16 - 12 = 4 s

Acceleration can be found using the 1st equation of motion.

  v = u + at

⇒ a = (v - u) / t

   a = (0 - 25) / 4

∴ a = -25/4

The negative value indicates the deceleration or the retarded motion.

Now the distance traveled can be found using the 3rd equation of motion.

v² - u² = 2aS

S = (v² - u²) / 2a

S = (0² - 25²) / (2 × -25/4)

S = -625 / (-25/2)

S = 25 × 2

S = 50 m