Question

what is the distance when the acceleration is 4m/s² and the time is 10 sec​

Answer 1

Using the relation s = u t+ ½ a t²

Using the relation s = u t+ ½ a t²What distance will it covering 10 seconds after the start? Time t = 10 sec. Velocity v after 10 sec= u + a t = 0 m/s + 4 m/s² × 10 s =40 m/s.

Answer 2

Step-by-step explanation:

distance =speed xtime or s=1/2at2

2s=4x100

s=200m