What is the divisor if quotient is 97 and dividend is 1455 ( reminder is 0 )
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We know that the division algorithm states that:
Dividend=(Divisor×quotient)+Remainder
Here it is given that the dividend is p(x)=4x
3
+2x
2
−10x+2, the divisor is g(x), the quotient is 2x
2
+4x+1 and the remainder is 5, therefore,
4x
3
+2x
2
−10x+2=[g(x)(2x
2
+4x+1)]+5
⇒g(x)=
2x
2
+4x+1
4x
3
+2x
2
−10x+2
The division is shown above.
Hence, from the above division, we get that the divisor is g(x)=2x−3
Answered By
toppr
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