Math, asked by coronavv, 9 months ago

What is the domain and range of f(x)= root(16-x^2) ?

Answers

Answered by BrainlyEmpire
5

Answer:

Hello mate..

Step-by-step explanation:

F(x)=√(16-xsq)

For Domain

√(16-xsq)=0

16-xsq=0

xsq= 16

x= +-4

So Domain= R-{+4,-4} Ans

For Range

y= √16-xsq

ysq= 16-xsq

xsq = 16-ysq

x= √16-ysq

For Range

√16-ysq=0

16-ysq=0

y= +-4

So Range = R-{+4,-4} Ans

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Answered by buddigaduu
0

Answer:

(

x

)

=

16

x

2

, for domain under root should not be

negative quantity.  

16

x

2

0

or

16

x

2

or

x

2

16

x

4

or

x

4

. Domain :  

4

x

4

or

[

4

,

4

]

Range :  

f

(

x

)

is maximum at  

x

=

0

,

f

(

x

)

=

4

and

f

(

x

)

is minimum at  

x

=

4

,

f

(

x

)

=

0

Range :  

0

f

(

x

)

4

or

[

0

,

4

]

Domain :  

4

x

4

, in interval notation :  

[

4

,

4

]

Range:  

0

f

(

x

)

4

, in interval notation :  

[

0

,

4

]

graph{(16-x^2)^0.5 [-10, 10, -5, 5]}

Step-by-step explanation:

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