What is the domain and range of f(x)= root(16-x^2) ?
Answers
Answer:
Hello mate..
Step-by-step explanation:
F(x)=√(16-xsq)
For Domain
√(16-xsq)=0
16-xsq=0
xsq= 16
x= +-4
So Domain= R-{+4,-4} Ans
For Range
y= √16-xsq
ysq= 16-xsq
xsq = 16-ysq
x= √16-ysq
For Range
√16-ysq=0
16-ysq=0
y= +-4
So Range = R-{+4,-4} Ans
HOPE IT WILL HELP YOU ❣️❣️..
PLZ MARK AS BRAINLIST ANSWER ❣️..
PLZ FOLLOW ME ✔️✔️✔️
Answer:
(
x
)
=
√
16
−
x
2
, for domain under root should not be
negative quantity.
16
−
x
2
≥
0
or
16
≥
x
2
or
x
2
≤
16
∴
x
≤
4
or
x
≥
−
4
. Domain :
−
4
≤
x
≤
4
or
[
−
4
,
4
]
Range :
f
(
x
)
is maximum at
x
=
0
,
f
(
x
)
=
4
and
f
(
x
)
is minimum at
x
=
4
,
f
(
x
)
=
0
Range :
0
≤
f
(
x
)
≤
4
or
[
0
,
4
]
Domain :
−
4
≤
x
≤
4
, in interval notation :
[
−
4
,
4
]
Range:
0
≤
f
(
x
)
≤
4
, in interval notation :
[
0
,
4
]
graph{(16-x^2)^0.5 [-10, 10, -5, 5]}
Step-by-step explanation: