Question

What is the
domain of
‌log (2x+1) (3-x) > 2 base (2-x)​

Answer 1

Answer:

Step-by-step explanation:

'f(x) = (log_2(x+3))/(x^2+3x+2)`

For `f(x)` to be defined:

(i) `(x+3) gt 0 =>x gt -3`

(ii) `x^2+3x+2 !=0 =>(x+1)(x+2) ! = 0 => x != -1 and x !=-2`

`:. ` Domain of `f(x)` will be `(-3,oo)-{-1,-2}.`