Question

What is the domain of the square root function graphed below?
On a coordinate plane, a curve opens down to the right and goes through quadrants 1 and 2. The curve starts at (negative 4, 0) and goes through (negative 3, 1) and (0, 2).
x greater-than-or-equal-to negative 4
x greater-than negative 4
x greater-than-or-equal-to 0
x greater-than 0

Answer 1

Given : On a coordinate plane, a curve opens down to the right and goes through quadrants 1 and 2. The curve starts at (negative 4, 0) and goes through (negative 3, 1) and (0, 2).

To Find : domain of the square root function graphed below

x greater-than-or-equal-to negative 4

x greater-than negative 4

x greater-than-or-equal-to 0

x greater-than 0

Solution:

The curve starts at (negative 4, 0) and goes through (negative 3, 1) and (0, 2).

 x      y

-4     0

-3     1

0     2  

Domain of the function is greater-than-or-equal-to negative 4

x ≥ - 4

y = √(x + 4)   is the graph

y is defined if x + 4 ≥  0

=> x ≥ - 4  

x ≥ - 4  is the domain of the square root function graphed

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Answer 2

Answer:

A) x ≥ -4

Step-by-step explanation:

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