Question

what is the dot product of two vectors of magnitudes 3 and 5,if angle between them is 60^@?

Answer 1

Explanation:

A.B = |A| |B| Cos 60°

= 15/2

=7.5 Ans.

Answer 2

Dot product between the two vectors is 7.5.

•) Let ā and ē be the two vectors such that their magnitudes are |a| = 3 and |e| = 5 and angle between them is Φ = 60°

•) Now we know in dot product,

ā•ē = |a|*|e|*cosΦ

=3*5*cos60

=15*½ = 7.5