what is the effect of force acting on a body when it acts such that it makes an angle with the velocity of a body? Give one example where the vertical velocity of a body is changing and horizontal velocity remains unaffected
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Suppose a force "F" acts at an angle "p" w.r.t. the velocity "u" of the body.
The force "F" can be broken into 2 components
(I) Fcosp , which is in the same direction as the velocity "u" and
(ii) Fsinp, , which is perpendicular to the direction of the velocity "u".
Suppose the mass of the body is "m".
The acceleration in the direction of the velocity =
Fcosp/m = (F/m) cosp (horizontal component)
Similarly, the acceleration in the direction perpendicular to the direction of the velocity =
Fsinp/m = (F/m) sinp (vertical component)
If the force is applied for the time "t", the vertical component of the velocity after the time "t"=
Vy = 0.5 (F/m)sinp t^2
And the horizontal component of the velocity after time "t"=
Vx= u + 0.5 (F/m)cosp t^2
The magnitude of the velocity after time "t"=
sqrt(Vx^2 + Vy^2)
The direction of this velocity after time "t" is at an angle "q" from the direction of the initial velocity "u", such that,
tanq = Vy/Vx
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The force "F" can be broken into 2 components
(I) Fcosp , which is in the same direction as the velocity "u" and
(ii) Fsinp, , which is perpendicular to the direction of the velocity "u".
Suppose the mass of the body is "m".
The acceleration in the direction of the velocity =
Fcosp/m = (F/m) cosp (horizontal component)
Similarly, the acceleration in the direction perpendicular to the direction of the velocity =
Fsinp/m = (F/m) sinp (vertical component)
If the force is applied for the time "t", the vertical component of the velocity after the time "t"=
Vy = 0.5 (F/m)sinp t^2
And the horizontal component of the velocity after time "t"=
Vx= u + 0.5 (F/m)cosp t^2
The magnitude of the velocity after time "t"=
sqrt(Vx^2 + Vy^2)
The direction of this velocity after time "t" is at an angle "q" from the direction of the initial velocity "u", such that,
tanq = Vy/Vx
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Answer:
then the compnent of force perpendicular to velocity will result in an additional velocity of particle perpendicular to previous velocity.
and the component of force parallel to the original velocity will increase or decrease the original velocity.
Exampe is the projectile motion the downward force changes the speed of particle in the vertical direction whereas the horizontal velocity remains unchanged.
Explanation:
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