What is the effective resistance of the resistors 2 Ω ,4 Ω and 5 Ω connected
in parallel ?
ANS:-1.05Ω
explain why??..
Answers
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effective resistance[(1/p)] = 1/2 + 1/4 + 1/5
[(1/p)] = (20 + 10 + 8)/40
[(1/p)] = (38)/40
p/1 = 40/38
effective resistance (p) = 1.05 ohm
hope it helps
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