What is the efficiency of a carnot's engine working between ice point and steam point.
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Answered by
220
efficiency = (Q1 - Q2)/Q1 = (T1 - T2)/T1
= (373 °K - 273° K)/373 °K
= 0.268
= (373 °K - 273° K)/373 °K
= 0.268
GovindKrishnan:
Thanks for this Great Answer Sir! ☺
Answered by
120
efficiency ={ input /out put } x 100
={(Q2 - Q1)/Q1} x 100
let Q1 , Q2 , T1 , and T2 relation in carnot engine .
Q2/Q1 =T2/T1
(Q2 - Q1 ) /Q1 = {(T2 - T1)/T1 } x 100
so,
efficiency = {(373 - 273)/373 } x 100
= 10000/373
=26.80 %
={(Q2 - Q1)/Q1} x 100
let Q1 , Q2 , T1 , and T2 relation in carnot engine .
Q2/Q1 =T2/T1
(Q2 - Q1 ) /Q1 = {(T2 - T1)/T1 } x 100
so,
efficiency = {(373 - 273)/373 } x 100
= 10000/373
=26.80 %
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