Question

What is the efficiency of simple machine if a load of 900kg is lifted with a velocity ratio of 4 and effortapplied is 300kg?

Answer 1

Explanation:

efficiency =

mechanical advantage/velocity ratio

MA = (load/effort) = (900/300)=3

efficiency = 3/4 = 0.75 = 75 %

Answer 2

Answer:

If a load of 900 kg is raised with a velocity ratio of 4, the efficiency of a simple machine is 75%.

Explanation:

Efficiency of a machine is conversion  of input energy  into work done . Efficiency can be calculated by (η)  

 η=  work done / input power

We  also know that,  

 Efficiency of simple machine is given as

η = $\frac{load}{ effort *Velocity Ratio }$

Given :   Load = 900 kg

              velocity ratio = 4

              effort = 300 kg

Now efficiency

η = $\frac{load }{effort * V.R.}$

η=$\frac{900}{(300)4}$

η = 0.75

Hence efficiency = 75%