Question

what is the Eigen value of function e^ax when operated on the operator d^n÷dx^n?​

Answer 1

Answer:

Explanation:

so eax is an eigenfunction of the operator linear differential operator dndxn of eigenvalue an. Conversely, the an-eigenspace of this operator (regarded as a map, e.g., from C∞(R) to itself) has dimension n, and it's not too hard to write down an explicit