Question

what is the electric field 30cm from a charge of 4×10^-9C​

Answer 1

Answer:

119.7 N/C is the answer

Explanation:

$Given: \: \: q =4×1 {10}^{ - 9}C, r = 30 \times {10}^{- 2} m$

$\boxed{E = \frac{1}{4\pi \epsilon_{o}} \frac{q}{ {r}^{2} } }$

$Here, \\ E = \frac{1}{4\pi \epsilon_{o} } \frac{4 \times {10}^{ - 9} }{30 \times {10}^{ - 2} } \\ \\ = 9 \times {10}^{9} \times 1.33 \times {10}^{ - 8} \\ = 119.7N/C$

Answer 2

Answer:

ha bahot bolla ...

tu bhi apna khyal rakh