Question

what is the electric field 30cm from a charge of 4×10^-9C​

Answer 1

Answer:

Force between these charges

Q1 = 6 × 10–9 C

Q2 = 4 × 10–9 C

K = 9 × 109 N – m2 C–2

r = 30 cm = 0.3 m

Assume at point P, we want to find electric field.

Net field at P = 3600 – 1350

Explanation:

hope it's helpful

Answer 2

Answer:

hii priyanshu..

yr mere bhai ko meri iñsta id pata chal gyi ..ab iñsta pe nhi aati me