Question

What is the electric field at 10 cm from an isolated point particle with a charge 2x 10-9 C?

Answer 1

Answer:

1800 N/C

Explanation:

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Answer 2

Answer:

The electric field for an isolated point charge is 1.8×10³N/C.

Explanation:

The electric field for an isolated charged particle at a distance of "r" from the charge is given as,

$E=\frac{KQ}{r^2}$               (1)

Where,

E=electric field for an isolated charged particle

k=coulombs constant=9×10⁹       (constant)

Q=charge on the particle

r=distance of the point from the charge

From the question we have,

Q=2×10⁻⁹C

r=10cm=10×10⁻²m

By substituting the value of Q and r in equation (1) we get;

$E=\frac{9\times 10^9\times 2\times 10^-^9}{(10\times 10^-^2)^2}=\frac{9\times 2}{100\times 10^-^4}=18\times 10^2=1.8\times 10^3N/C$

Hence, the electric field for an isolated point charge is 1.8×10³N/C.