Physics, asked by durgeshkvishnoi29, 6 months ago

What is the electric field intensity the mid point of the line joinging at 2 charge in vacume

Answers

Answered by Anonymous

2

Answer:

E=kq/(r/2)²

where k = 1/4(pie epsilon) = 9×10⁹

Explanation:

this is because at midpoint distance will become half so distance = r/2.

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