What is the electric field strength 2.0 mm above the center of the electrode?
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HEY HERE IS UR ANS
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q=80 nC=8*10^-8 C
Distance,r=2 mm=2*10^-3 m
Electric field,E=1/(4πε0) q/r^2
=9*10^9*8*10^-8/(2*10^-3)^2
=1.8*10^8 N/C
PLSSS MARK AS BRAINLIEST
The electric field is 1.8*10^8 N/C.
.........
q=80 nC=8*10^-8 C
Distance,r=2 mm=2*10^-3 m
Electric field,E=1/(4πε0) q/r^2
=9*10^9*8*10^-8/(2*10^-3)^2
=1.8*10^8 N/C
PLSSS MARK AS BRAINLIEST
The electric field is 1.8*10^8 N/C.
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