Question

what is the electric field strength at a distance of 9 cm from a charge of 7x10-6 uc?​

Answer 1

Explanation:

Electric field strength due to charge =7μC= 7x10-6 C

distance =9cm= 9x10-2 m

$e = k \frac{q}{ {r}^{2} }$

where e is the electric field strength

q is the charge given and r is the distance

k is the columb constant

$k = \frac{1}{4\pi \: e0} = 9 \times {10}^{9}$

So

$e = 9 \times {10}^{9} \frac{7 \times {10}^{ - 6} }{ {(9 \times {10}^{ - 2}) }^{2} }$

$e = 7.7 \times {10}^{6}$