Question

What is the electric flux through a cube enclosed a charge of 1C

Answer 1

According to gauss's law

Electric flux through the closed surface is 1/e times the charge enclosed by it.

Where,

e is electrical permittivity

Here,

Electric flux=q/6e

1/6×8.85×10^-12=1.475×10^-12 Nm^2C^-1

I hope this helped you

Answer 2

Given that,

Charge, Q = 1 C

To find,

Electric flux through the surface.

Solution,

Gauss's law states that the net electric flux through a closed surface is given by :

$\phi=\dfrac{q}{\epsilon_o}$

For a cube, flux will be through 6 surfaces. So,

$\phi=\dfrac{q}{6\epsilon_o}\\\\\phi=\dfrac{1}{6\times 8.85\times 10^{-12}}\\\\\phi=1.88\times 10^{10}\ Nm^2/C$

Hence, this is the required solution.

Learn more,

Gauss's law

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