what is the electric flux through a cube of side 1 cm which encloses an electric dipole
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Answered by
96
the net electric charge inside the closed cubic surface = 0, as the dipole consists of equal and opposite charges.
The net electric flux through a closed 3-d surface = charge enclosed/epsilon.
So net electric flux = 0.
The net electric flux through a closed 3-d surface = charge enclosed/epsilon.
So net electric flux = 0.
Answered by
27
Hey !!
Zero ( as net charge enclosed by the surface is zero ).
DETAILED EXPLANATION
In a cubic surface, the net electric charge will be zero since dipole carries equal and opposite charges. It is observed that the net electric flux through closed surface will be
= Charge enclosed / ε₀
and because the charge enclosed is zero.
electric flux is also zero.
Good luck !!
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