what is the electric flux through a cube of side 1 cm which encloses an electric dipole?
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Answered by
87
Answer:
0 is Ur answer mate
Since net charge enclosed in the surfaces bound by the cube is zero(dipole consists of equal and opposite charges), according to the Gauss Law, it can be claimed that the net flux through the cube is zero.
Explanation:
ϵ0 = absolute electric permittivity of free space so, in the given case, cube encloses an electric dipole. Therefore, the net charge enclosed within the cube is zero. i.e. q = 0.
Answered by
2
Answer:
Answer is this: ϵ0 = absolute electric permittivity of free space so, in the given case, cube encloses an electric dipole. Therefore, the net charge enclosed within the cube is zero. i.e. q = 0.
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