What is the electron configuration for the transition metal ion in each of the following compounds? [Ni(H2O)6]Br2 , [Cr(H2O)4(NO2)2]
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Answer:
1.
Ni:(0)-(6*0)=0
2.
Cr:(0)-[0*4+2*(-1)]=0-(-2)=2
Explanation:
oxidation_state(h20)=0
oxidation_state(no2)=-1
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