Question

what is the electron dot structure of BF2​

Answer 1

Step 1: Find valence e- for all atoms. Add them together.

Be:2

F:7x2=14

Total=16

Step2: Find octet e- for each atom and add them together.

Be:4*

F:8x2=16

Total=20

*Beryllium is exception to octet rule and get 4 electrons instead of 8.

Step3: Gives you bonding e-. Subtract step 1 total from step 2

20-16=4e-

Step 4: Find number of bonds by diving the number in step 3 by 2(because each bond is made of 2 e-)

4e-/2= 2 bond pairs

Step 5: Find the number of nonbonding (lone pairs) e-. Subtract step 3 number from step 1.

16-4= 12e-=6 lone pairs

Use information from step 4 and 5 to draw the lewis structure.

Beryllium goes in the centre.Make sure both fluorines get 8 electron.

Lone pairs are in green. Bond pairs are in purple.

BeF2 lewis structure