What is the electronic configuration of element Y whose mass no. is 27 and no.of neutron is 14?
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atomic mass = no.of neutron+no.of electron
27=14+ no.of electron
27-14= no.of electron
no.of electron=13
means atomic number is 13 (no.of electron is equal atomic number)
Y element is aluminum , atomic number 13
electronic configuration- k shell=2,L=8,M =3
valency of aluminium is 3
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Answer:
Electronic Configuration: 2.8.3
Explanation:
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