Question

what is the electronic configuration of fe in K3[Fe(C2O4)3]

Answer 1

The oxidation numbers are K=+1

C2O4= -2

So,According to formula...k=+3

c2o4= -6

oxidation no. of Fe

3+x-6=0

x=+3.........It is ferric ion present in potassium ferric oxalate

Answer 2

In complexes we calculate electronic configuration of metals only

Explanation:

$K_{3}[Fe(C_{2}O_{4})_{3}]$

K = +1 charge

$C_{2}O_{4}$(oxalate) = -2 charge

Fe = ?

3K will give -3 charge on metal complex, because it has +1 charge(3*1=3)

so, $[Fe(C_{2}O_{4})_{3}]^{-3}$

x+3*(-2)=-3

x-6=-3

x= +3

so, Fe has +3 oxidation state and now we will calculate electronic configuration

Fe has $3d^{6}4s^{2}$ configuration

and here it is in +3 oxidation state

so here electronic configuration of the complex is $3d^{5}$