What is the elements of set F={x:x∈N, √x^2+1 = 2 (the end of the square root are after 1)}
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Answer:
F will be an empty set!
Step-by-step explanation:
√(x^2 +1)=2
x^2+1= 4 (squarring both sides)
x^2 =3
x = +/- √3
but both are not natural numbers.....and all elements of f are natural so no elements exists in f
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