What is the emf when three cells of 3v 1.5v and 2v are connected
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This circuit will create a short circuit between the cells. The difference in voltage will cause all the cells to equalise - if the voltage-charge was linear, then all cells would become 3v (but in reality it is more complex than simply a linear relation).
It simply does not make sense if the resistance is 0, as the 4v battery must lose the extra 2v after flowing (in reverse) through the 2v cell - without resistance, this results in a divide by 0 error (I=V/R -> I=2/0).
To take realism into account, the most likely scenario is that the cells would explode due to the significant current drawn during the equalisation of the cells as power is dissipated (0 internal resistance is simply not realistic). This could be prevented by placing resistors between each cell to limit current.
TL;DR: The cells would equalise (but probably explode in the process due to massive currents involved) to produce a voltage comparable to the average cell voltage. If adequate precautions (resistors/current limiters) are used, the result will be 3 cells at approximately 3v each. Since the cells are in parallel, the total voltage output would be the same as a single cell (approximately 3v).
Also, many batteries are non-rechargeable, and so even with current limiting resistors, problems can still occur during equalisation.