Question

what is the emperical formul for a compound that contains 17.34% hydrogen and 82.55% carbon by mass

Answer 1

Answer:

So lets get started..

So lets get started..Divide by relative atomic masses to get the mole ratio  

So lets get started..Divide by relative atomic masses to get the mole ratio  Mole ratio C : H = 82.66/12.01 : 17.34/1.008 = 6.88 : 17.20  

So lets get started..Divide by relative atomic masses to get the mole ratio  Mole ratio C : H = 82.66/12.01 : 17.34/1.008 = 6.88 : 17.20  To get this as a 1:x ratio, divide both by the smaller of the two  

So lets get started..Divide by relative atomic masses to get the mole ratio  Mole ratio C : H = 82.66/12.01 : 17.34/1.008 = 6.88 : 17.20  To get this as a 1:x ratio, divide both by the smaller of the two  Mole ratio C : H = 6.88/6.88 : 17.20/6.88 = 1 : 2.5  

So lets get started..Divide by relative atomic masses to get the mole ratio  Mole ratio C : H = 82.66/12.01 : 17.34/1.008 = 6.88 : 17.20  To get this as a 1:x ratio, divide both by the smaller of the two  Mole ratio C : H = 6.88/6.88 : 17.20/6.88 = 1 : 2.5  To get this as a whole number ratio, multiply both by 2  

So lets get started..Divide by relative atomic masses to get the mole ratio  Mole ratio C : H = 82.66/12.01 : 17.34/1.008 = 6.88 : 17.20  To get this as a 1:x ratio, divide both by the smaller of the two  Mole ratio C : H = 6.88/6.88 : 17.20/6.88 = 1 : 2.5  To get this as a whole number ratio, multiply both by 2  Mole ratio C : H = 2 : 5  

So lets get started..Divide by relative atomic masses to get the mole ratio  Mole ratio C : H = 82.66/12.01 : 17.34/1.008 = 6.88 : 17.20  To get this as a 1:x ratio, divide both by the smaller of the two  Mole ratio C : H = 6.88/6.88 : 17.20/6.88 = 1 : 2.5  To get this as a whole number ratio, multiply both by 2  Mole ratio C : H = 2 : 5  Therefore, the empirical formula is C2H5

So lets get started..Divide by relative atomic masses to get the mole ratio  Mole ratio C : H = 82.66/12.01 : 17.34/1.008 = 6.88 : 17.20  To get this as a 1:x ratio, divide both by the smaller of the two  Mole ratio C : H = 6.88/6.88 : 17.20/6.88 = 1 : 2.5  To get this as a whole number ratio, multiply both by 2  Mole ratio C : H = 2 : 5  Therefore, the empirical formula is C2H5Hope this helps you!!

So lets get started..Divide by relative atomic masses to get the mole ratio  Mole ratio C : H = 82.66/12.01 : 17.34/1.008 = 6.88 : 17.20  To get this as a 1:x ratio, divide both by the smaller of the two  Mole ratio C : H = 6.88/6.88 : 17.20/6.88 = 1 : 2.5  To get this as a whole number ratio, multiply both by 2  Mole ratio C : H = 2 : 5  Therefore, the empirical formula is C2H5Hope this helps you!!#Be Brainly

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