Question

What is the empirical formula for a compound that is found to contain 10.15 mg P and 34.85 mg Cl?

Answer 1

29-May-2016 · PCl_3 %P = (10.15*mg)/(( 34.85+10.15)*mg)xx100% = 22.6% %Cl = ( 34.85*mg)/((34.85+10.15)*mg)xx100% = 77.4 % ...