what is the empirical formula for
hydrogen 6.22% oxygen 69.5% sodium 14.31% sulphur 9.97%
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Explanation:
Compound on analysis gave Na = 14.31% S = 9.97% H= 6.22% and O= 69.5% calculate the molecular formula of the compound if all the hydrogen in the compound is present in combination with oxygen as water of crystallization. (molecular mass of the compound is 322).
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here are both..
ur empirical and molecular formula.
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