Question

What is the empirical formula of a compound composed of 18g magnesium and 7g nitrogen?(At. Mass = Mg =24, N =14)

Answer 1

Answer:

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Answer 2

Given,

R.M.M of Mg = 24 g, N = 14 g

Given Mass of Mg = 18 g, N = 7 g

Moles of Mg = 18/24

= 0.75

Moles of N = 7/14

= 0.5

Between these, the smallest mole is that of Nitrogen, So,

Simplest Ratio of Mg = 0.75/0.5

= 2

Simplest Of N = 0.5/0.5

= 1

Empirical Formula = Mg₂N

I hope this helps.