what is the empirical formula of a compound containing 60% sulphur and 40% oxygen by mass ??
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Answers
Answered by
4
Answer:
The ratio of S:O=40:60 by mass.
The molar mass of S=32
The number of moles of S=
32
40
=1.25
The molar mass of O=16
The number of mole of O=
16
60
=3.75
Molar ratio of S:O=1.25:3.75=1:3
The empirical formula would be =SO
3
Answered by
0
Explanation:
The empirical formula should be SO3
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