Question

What is the empirical formula of a compound with 35.94% aluminum and 64.06% sulfur? A. AlS B. Al4S6 C. AlS2 D. Al2S3 E. AlS3

Answer 1

Answer:

c. is the correct answer

Answer 2

Question

What is the empirical formula of a compound with 35.94% aluminum and 64.06% sulfur? A. AlS B. Al4S6 C. AlS2 D. Al2S3 E. AlS3

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Given:

% Al = 35.94

% S = 64.06

To determine:

Empirical formula of a compound with the above composition

Explanation:

Atomic wt of Al = 27 g/mol

Atomic wt of S = 32 g/mol

Based on the given data, for 100 g of the compound: Mass of Al = 35.94 g and mass of S = 64.06 g

# moles of Al = 35.94/27 = 1.331

# moles of S = 64.06/32 = 2.002

Divide by the smallest # moles:

Al = 1.331/1.331 = 1

S = 2.002/1,331 = 1.5 ≅ 2

Empirical formula = AlS₂

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