Question

What is the empirical formula of a following compound if a sample contain 0.0130 mol C, 0.0390 mol H, and 0.0065 mol O?

Answer 1

$C_{n}H_{m} O_{p} = C_{2}H_{6}O$

Explanation:

The empirical formula is the formula that describes which atoms are in the molecule of that compound and what is the simplest ratio of the number of those atoms.

As we know,

In order to derive the empirical formula, it must be divided through the smallest molar quantity.

Since the smallest molar quantity is of Oxygen;

C = 0.0130 mol/0.0065 mol = 2C

H = 0.0390 mol/0.0065 mol = 6H

O = 0.0065 mol/0.0065 mol = 1 O

Thus, the empirical formula would be $C_{n}H_{m} O_{p} = C_{2}H_{6}O$

Learn more: Empirical Formula

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