Question

What is the empirical formula of kaolin, percentage composition of which is as under; al2o3 = 39.5%, sio2 = 46.6% , h2o =13.9%.​

Answer 1

Answer:

KAOLIN

KAOLIN Structure

KAOLIN

CAS No.1332-58-7

Chemical Name:KAOLIN

CBNumber:CB6300504

Molecular Formula:H2 Al2 O8 Si2 . H2 O

Formula Weight:258.16

MOL File:1332-58-7.mol

KAOLIN Property

Melting point: :1750 °C

Density :2,6 g/cm3

refractive index :1.6200

storage temp. :Storage temperature: no restrictions.

solubility :Practically insoluble in diethyl ether, ethanol (95%), water, other organic solvents, cold dilute acids, and solutions of alkali hydroxides.

form :Powder

color :75-96, Hunter Brightness

PH :6-7 (50g/l, H2O, 20℃)(slurry)

Water Solubility :insoluble H2O, dilute acids and alkali hydroxides [HAW93]

Stability: :Stable. Substances to be avoided include strong oxidizing agents.

InChIKey :NLYAJNPCOHFWQQ-UHFFFAOYSA-N

Indirect Additives used in Food Contact Substances :CLAY (KAOLIN)

SCOGS (Select Committee on GRAS Substances) :Clay (kaolin) (packaging)

EWG's Food Scores :1

FDA UNII :24H4NWX5CO

EPA Substance Registry System :Kaolin (1332-58-7)

Safety

Safety Statements :22-24/25

WGK Germany :-

RTECS :GF1670500

TSCA :Yes

HS Code :25070090

NFPA 704: 0 2 0

Explanation:

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Answer 2

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Answer:

Al2O3.2SiO2.2H2o

Molar masses

Molar mass of Al2O3 =102 g/mol

Molar mass of SiO2 = 60 g/mol

Molar mass of H2O = 18 g/mol

We can consider the percentages as masses:-

Moles of Al2O3 = 39.5/102 = 0.38

Moles of SiO2 = 46.6/60 = 0.78

Moles of H2O = 13.9/18 = 0.77

Mole ratio

Moles of Al2O3 = 0.38/0.38 =  1 = 1

Moles of SiO2 =0.78/0.38 = 2.05 = 2

Moles of H2O = 0.77/0.38 = 2.03 = 2

The empirical formula:-

      Al2O3.2SiO2.2H2o

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