Question

What is the empirical formula of vanadium oxide if 2.74 gram of the metal oxide contains 1.53 gram of metal?

Answer 1

Hello Dear.

Here is the answer---

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Mass of Vanadium Oxide = 2.74 grams.
Mass of Vanadium = 1.53 grams.
% comp. of Vanadium = (Mass/Mass of the oxide) × 100%
= (1.53/2.74) ×  100%
= 55.84%


Mass of Oxygen = 2.74 - 1.53
= 1.21 grams.
% Composition of Oxygen = (1.21/2.74) × 100%
 = 44.16 %.

Now, 
Refers to the Attachment for the Question,


Empirical Formula is V₂O₅.


Empirical Formula is Calculated in the Attachment. Steps of Calculating the Formula is given below →


1) Make a Table which have 3 Rows and 6 Columns.
2) ⇒ In First Columns write the Name of the elements. ⇒ In second Columns write the Given % Composition, ⇒ In third column write the atomic mass of the elements,⇒ In fourth columns, Calculate the Number of atoms by dividing the atomic masses of the elements with the  given % Composition. ⇒ In 5th columns, write the Simplest Ratio.

3) In the Final Column, Calculate the Whole number ratio which cannot be in Decimal. In the Given Question, Since, the Simplest Ratio of the Oxygen is 2.5 thus we have to Multiply the whole ratio by 2.

4) Finally Calculate the Empirical Formula, by substituting the Whole number ratio into the Each elements.Thus, Empirical Formula of the Compound will be V₂O₅.


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Hope it helps.

Answer 2

Answer:

Hope this answer helps u.....